Foreclosure. $289,900. 4 bed. 1 bath. 0.4 acre lot. 115 Delmar Dr. Simpsonville, SC 29680. Additional Information About 6 Allamanda Way Lot 8, Simpsonville, SC 29680. See 6 …Check all that apply. f (x) = 5 RootIndex 3 StartRoot 16 Endroot Superscript x Baseline = 5 (2 RootIndex 3 StartRoot 2 EndRoot) Superscript x f (x) = 2.3 (8) Superscript one-half x Baseline = 2.3 (4) Superscript x f (x) = 81 Superscript StartFraction x Over 4 EndFraction Baseline = 3 Superscript x f (x) = three-fourths StartRoot 27 EndRoot ...Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, " It can be written as where The given expression is whereThe expression RootIndex 3 StartRoot StartFraction 75 a^7 b^4 Over 40 a^13 c^9 EndFraction EndRoot is equivalent to (5ab^4)/(2ac^3).. To simplify the given expression, we can use the properties of radicals and simplify the numerator and denominator separately.. Step 1: Simplify the numerator:Indices Commodities Currencies StocksWILL MARK BRAINLIEST Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Superscript 6 Baseline y Superscript 11 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y > 0. answers.Let's see some more problems and our step by step solver will simplify the radical expressions. Please click "Solve Similar" for more examples. Solve similiar problemEnter your own problem. 3. root (3,27x^2y^4) = root (3,3^3x^2y^4) = root (3,3^3z^2y^3y. = root (3,3^3y^3)root (3,x^2y)Which expression is equivalent to RootIndex 3 StartRoot 256 x Superscript 10 Baseline y Superscript 7 Baseline EndRoot? a.4 x squared y (RootIndex 3 StartRoot x squared y cubed EndRoot) b. 4 x cubed y squared (RootIndex 3 StartRoot 4 x y EndRoot) c. 16 x cubed y squared (RootIndex 3 StartRoot x y EndRoot) d. 16 x Superscript 5 Baseline y cubed ...Which expression is equivalent to RootIndex 3 StartRoot x Superscript 5 Baseline y EndRoot? Click the card to flip. B- x5/3 y1/3. Quizlet has study tools to help you learn anything. Improve your grades and reach your goals with flashcards, practice tests and expert-written solutions today.Calculus. Calculus questions and answers. RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot.6/y^8. Anja simplified the expression 10x^-5/-5x^10 to 15/x^15. What mistake did Anja make? She subtracted the coefficients instead of dividing them. Describe how to simplify the expression 3^-6/3^-3. NOT Multiply the bases and then subtract the exponents. What is the quotient of -8x^6/4x^-3?Free Logarithmic Form Calculator - present exponents in their logarithmic forms step-by-stepQuestion: StartFraction x Superscript two thirds Baseline x Superscript one half Baseline Over left parenthesis x StartRoot x Superscript negative 3 Baseline EndRoot RootIndex 3 StartRoot x squared EndRoot right parenthesis Superscript 6 Baseline EndFraction in the form x Superscript s Baseline.What is the following simplified product? Assume x greater-than-or-equal-to 0 2 StartRoot 8 x cubed EndRoot (3 StartRoot 10 x Superscript 4 Baseline EndRoot minus x StartRoot 5 x squared EndRoot) 24 x cubed StartRoot 5 x EndRoot minus 4 x squared StartRoot 10 x EndRoot 24 x cubed StartRoot 5 x EndRoot minus 4 x cubed StartRoot 10 x EndRoot 24 x cubed StartRoot 5 EndRoot minus 4 x cubed ...profile. JackelineCasarez. Answer: Option (a) is correct. Step-by-step explanation: As given in the question the expreession is as follows . As. Now put the above expression given in the question . arrow right.Find an answer to your question What is the simplified form of StartRoot 144 x Superscript 36 Baseline EndRoot? 12x6 12x18 72x6 72x18. nschroeder nschroeder 28.04.2020 Math ... Find the value of 3276 x 3-3 2 7 6 x 2 solve the equation 3 - 7/2 Y + 16/ 3y- 5 = Y - 2y + 2 Previous Next We're in the know Company Careers Advertise with us Terms of ...Dec 7, 2020 · We can simplify this by taking the square root of each pair of 7s and multiplying them together: StartRoot 1,225 EndRoot = StartRoot 5^2 × 7^2 EndRoot = 5 × 7 = 35 Therefore, the simplest form of √1,225 is 35. D- 3 cubed squareroot 5^7. Which expression is equivalent to (StartFraction 4 Superscript five-fourths Baseline time 4 Superscript one-fourth Baseline Over 4 Superscript one-half baseline EndFraction) Superscript one-half? C- 2. Which of the following is equivalent to 16 Superscript three-fourths? B- 8. What is the simplified form of the following expression? Assume y not-equals 0. RootIndex 3 StartRoot StartFraction 12 x squared Over 16 y EndFraction EndRoot StartFraction 2 (RootIndex 3 StartRoot 6 x squared y squared EndRoot) Over y EndFraction StartFraction RootIndex 3 StartRoot 12 x squared y EndRoot Over 2 y EndFraction StartFraction x (RootIndex 3 StartRoot 3 y EndRoot) Over 2 y ...to save your graphs! Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.Click here 👆 to get an answer to your question ️ Describe how to simplify the expression StartFraction 3 Superscript negative 6 Baseline Over 3 Superscript n ... ET 6.15& 6.16 POSSIBLE P The height in feet of a seat on a Ferris wheel is given by the function h(t)=50 sin +60. ...Which expression is equivalent to RootIndex 4 StartRoot StartFraction 24 x Superscript 6 Baseline y Over 128 x Superscript 4 Bas. ... Assume x not-equals 0 and y StartFraction RootIndex 4 StartRoot 3 EndRoot Over 2 x squared y EndFraction StartFraction x (RootIndex 4 StartRoot 3 EndRoot) Over 4 y squared EndFraction ... Simplify the expression ...We have the right solution; What is the following product? RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x Superscript 9 Baseline EndRoot ☝️! At redmondmathblog you can get the correct answer to any question on 💥: algebra trigonometry plane geometry solid geometry probability …Assume x greater-than-or-equal-to 0 (StartRoot 6 x squared EndRoot 4 StartRoot 8 x cubed EndRoot) (StartRoot 9 x EndRoot minus x StartRoot 5 x Superscript 5 Baseline) 3 x StartRoot 6 x EndRoot x Superscript 4 Baseline StartRoot 30 x EndRoot 24 x squared 8 x Superscript 5 Baseline StartRoot 10 x EndRoot 3 x StartRoot 6 x EndRoot x Superscript 4 ...Calculus. Calculus questions and answers. RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot.Question: Find the derivative. f (x)equalsln left parenthesis x e Superscript StartRoot x EndRoot Baseline plus 5 right parenthesisQuestion content area bottomPart 1f prime left parenthesis x right parenthesisequals enter your response here. Find the derivative. Here's the best way to solve it.Algebra. Simplify square root of 64x. √64x 64 x. Rewrite 64 64 as 82 8 2. √82x 8 2 x. Pull terms out from under the radical. 8√x 8 x. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.View Notes - week one notes.docx from MA 135 at Park University. 7) negative eight (a) 00 (b) 2222 (c) thirds− 83 (d) StartRoot 49 EndRoot49 (e) StartRoot 2 EndRoot2 (f) 4.284.28 To identify to whichClick here 👆 to get an answer to your question ️ What is the simplified form of StartRoot 64 x Superscript 16 Baseline EndRoot? 8x4 8x8 32x4 32x8The answer of the given question based on the expression is equivalent expression to log Subscript 12 Baseline StartFraction x Superscript 4 Baseline StartRoot x cubed minus 2 EndRoot Over (x + 1) Superscript 5 Baseline EndFraction are given below,. What is Expression? In mathematics, expression is combination of numbers, symbols, and operators that represents value or quantity.Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, " It can be written as where The given expression is where16 people helped. report flag outlined. Answer: ... StartFraction RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot Over x squared EndFraction x cubed (RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot). star. 4.2/5. heart. 9. verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice ...Algebra. Simplify square root of 64x^16. √64x16 64 x 16. Rewrite 64x16 64 x 16 as (8x8)2 ( 8 x 8) 2. √(8x8)2 ( 8 x 8) 2. Pull terms out from under the radical, assuming positive real numbers. 8x8 8 x 8. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step ...What is the simplified form of StartRoot 400 x Superscript 100 Baseline EndRoot ? 200x Superscript 10 200x Superscript 50 20x Superscript 10 20x Superscript 50 star 4.8 /5Which expression is equivalent to rootindex 4 startroot startfraction 16 x superscript 11 baseline y superscript 8 baseline over 81 x superscript 7 baseline y superscript 6 baseline endfraction endroot? assume x greater-than 0 and y not-equals 0. verified. Verified answer.What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) + 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y Superscript 5 Baseline) 4 x (RootIndex 3 StartRoot 2 y EndRoot) + 12 x squared y (RootIndex 3 StartRoot 2 y squared EndRoot) 8 x (RootIndex 3 StartRoot x y EndRoot) + 12 x cubed y squared (RootIndex …A set of flashcards for Math II Sem 2 students to practice the square root function. One card shows the factor tree for 1,225 and asks for the simplest form of .Find an answer to your question What values of c and d make the equation true? rootindex 3 startroot 162 x superscript c baseline y superscript 5 baseline endro ... When we simplify the cube root of 162, it is 3 as 162 is equal to 3⁴ ... (RootIndex 3 StartRoot x y EndRoot) 16 x Superscript 5 Baseline y cubed (RootIndex 3 StartRoot y EndRoot) ...A. (x | all real numbers ); ( | y>0 ) Simplify the function f (x)=1/3 (81)^3x/4. Then determine the key aspects of the function. 13, 27, all real numbers, y>0. Explain why the square root of a number is defined to be equal to that number to the 1/2 power. (Put this in your own words) Squaring and square root are inverses, so one should "undo ...Simplify Radicals (with variables) • Activity Builder by ... - Desmos ... Loading...Dec 7, 2020 · We can simplify this by taking the square root of each pair of 7s and multiplying them together: StartRoot 1,225 EndRoot = StartRoot 5^2 × 7^2 EndRoot = 5 × 7 = 35 Therefore, the simplest form of √1,225 is 35. Mac: There are a few great tools for analyzing your Mac's disk space, but they're all pretty advanced. Disk App simplifies things to make it easy to clear up space on your hard dri...The new USPS Ground Advantage service can streamline your small business shipping needs with reduced prices and improved reliability. U.S. Postal Service is ready to launch a new s...May 20, 2020 · Simplify the function f(x) = 7((RootIndex 3 StartRoot 54 EndRoot Superscript x Baseline)). Then answer the questions below. The initial value for the function is . The simplified base for the function is RootIndex 3 StartRoot 2 EndRoot. The domain of the function is . The range of the function is . Simplify Radicals (with variables) • Activity Builder by ... - Desmos ... Loading...The question asks to simplify the expression StartRoot 144 x Superscript 36 EndRoot. First, we break down the square root of 144, which is 12, as 144 is a perfect square (12 x 12 = 144). Since the exponent of x is even (36), we can take the square root of x³⁶ by halving the exponent, which gives us x¹⁸.Write a in the form aequalsa Subscript Upper TTplusa Subscript Upper NN at the given value of t without finding T and N. r (t)equalsleft parenthesis e Superscript t Baseline sine t right parenthesisiplusleft parenthesis e Superscript t Baseline StartRoot 6 EndRoot right parenthesisjplusleft parenthesis e Superscript t Baseline cosine t right.Simplify square root of (72x^16)/(50x^36) Step 1. Reduce the expression by cancelling the common factors. Tap for more steps... Step 1.1. Factor out of . Step 1.2. Factor out of . Step 1.3. Cancel the common factor. ... Step 6. Pull terms out from under the radical, assuming positive real numbers.Which expression is equivalent to RootIndex 4 StartRoot StartFraction 16 x Superscript 11 Baseline y Superscript 8 Baseline Over 81 x Superscript 7 Baseline y Superscript 6 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y not-equals 0. See answer Advertisement Advertisement nandhuFF nandhuFFWhich expression is equivalent to RootIndex 4 StartRoot StartFraction 16 x Superscript 11 Baseline y Superscript 8 Baseline Over 81 x Superscript 7 Baseline y Superscript 6 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y not-equals 0. See answer Advertisement Advertisement nandhuFF nandhuFFWhich expression is equivalent to RootIndex 3 StartRoot 256 x Superscript 10 Baseline y Superscript 7 Baseline EndRoot? a.4 x squared y (RootIndex 3 StartRoot x squared y cubed EndRoot) b. 4 x cubed y squared (RootIndex 3 StartRoot 4 x y EndRoot) c. 16 x cubed y squared (RootIndex 3 StartRoot x y EndRoot)5x (8x2 -2x) d. 2x 10x-2x 5. 4x3 4x2 (2^3 32x2 - x3 2x) b. 5 of 6 slide. a. and c. last slide. b. and c. Study with Quizlet and memorize flashcards containing terms like find the simplified product 2x3•18x5, find the simplified product 3 9x4 • 3 3x8, 2 5x3 (-3 10x2 and more.This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Evaluate the following integral. Integral from nothing to nothing StartFraction dx Over StartRoot x squared minus 484 EndRoot EndFraction∫dxx2−484 , xgreater than>22 What substitution will be the most ...Rootindex 4 StartRoot 16 EndRoot Superscript 3x Rootlndex 4 x StartRoot 16 EndRoot cubed 3 Rootindex 3 StartRoot 16 End Root Superscript 4 x E Rootindex 3 x StartRoot 16 End Root Superscript 4 . star. 4.4/5. ... (2 Superscript one-half Baseline times 2 Superscript three-fourths Baseline) squared? RootIndex 4 StartRoot 2 cubed EndRoot StartRoot ...The equivalent expression to RootIndex 3 StartRoot StartFraction 75 a Superscript 7 Baseline b Superscript 4 Baseline Over 40 a Superscript 13 Baseline c Superscript 9 Baseline EndFraction EndRoot is StartFraction a cubed b (RootIndex 3 StartRoot 15 b squared EndRoot) Over 2 c cubed EndFraction. To understand why, let's break down the equation.What is the following product? Assume x greater-than-or-equal-to 0 (4 x StartRoot 5 x squared EndRoot 2 x squared StartRoot 6 EndRoot) squared 80 x Superscript 4 Baseline 8 x Superscript 4 Baseline StartRoot 30 x EndRoot 24 x Superscript 4 80 x Superscript 6 Baseline 8 x Superscript 5 Baseline 8 x Superscript 5 Baseline StartRoot 30 EndRoot 24 x Superscript 4 104 x Superscript 4 104 x ...A baseline acceptable credit score isn't set in stone. It varies according to economic conditions. However, in the aftermath of the Great Recession, "baseline acceptable" is higher...Check all that apply. f (x) = 5 RootIndex 3 StartRoot 16 Endroot Superscript x Baseline = 5 (2 RootIndex 3 StartRoot 2 EndRoot) Superscript x f (x) = 2.3 (8) Superscript one-half x Baseline = 2.3 (4) Superscript x f (x) = 81 Superscript StartFraction x Over 4 EndFraction Baseline = 3 Superscript x f (x) = three-fourths StartRoot 27 EndRoot ...2 a b c squared (RootIndex 3 StartRoot 4 a squared b cubed c EndRoot) 4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot) 8 a cubed b cubed c Superscript 4 Baseline (RootIndex 3 StartRoot b c EndRoot)StartFraction RootIndex 4 StartRoot 24 x cubed EndRoot Over 16 x Superscript 4 Baseline EndFraction RootIndex 4 StartRoot 12 x squared EndRoot. loading. See answers. loading. Ask AI. ... (RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot). star. 4.2/5. heart. 9. verified. Verified answer.How are the graphs of the functions f(x) = StartRoot 16 EndRoot Superscript x and g(x) = RootIndex 3 StartRoot 64 EndRoot Superscript xrelated? The functions f(x) and g(x) are equivalent. The function g(x) increases at a faster rate. The function g(x) has a greater initial value. The function g(x) decreases at a faster rate.15 x Superscript 6 Baseline y Superscript 8 Baseline (RootIndex 3 StartRoot x y EndRoot) 15 x cubed y Superscript 4 Baseline (RootIndex 3 StartRoot x y EndRoot) 8 x Superscript 6 Baseline y Superscript 8 Baseline (RootIndex 3 StartRoot x y EndRoot)The equivalent expression to x Superscript negative five-thirds is "StartFraction 1 Over RootIndex 3 StartRoot x Superscript 5 Baseline EndRoot EndFraction". Given: x Superscript negative five-thirds. Given options: StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot EndFraction ; StartFraction 1 Over RootIndex 3 StartRoot x Superscript 5 Baseline EndRoot EndFraction5 /5. heart. 3. verified. Verified answer. What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfraction endroot? assume x ≠ 0. star. 5 /5. heart.Final answer: The cube root of x^{10} when x is -2 simplifies to -8∛(-2), where a = -8 and b = -2.. Explanation: The student has asked to simplify the expression ∛ x^{10} when x is equal to -2. To simplify, we need to break down x^{10} into factors that are suitable for the cube root. Since negative numbers can have real cube roots, we can …RootIndex 4 StartRoot 16 EndRoot Superscript 3 x RootIndex 4 x StartRoot 16 EndRoot cubed RootIndex 3 StartRoot 16 EndRoot Superscript 4 x RootIndex 3 x StartRoot 16 EndRoot Superscript 4. star. 4.8/5. heart. 54. verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, how ...Check all that apply. f (x) = 5 RootIndex 3 StartRoot 16 Endroot Superscript x Baseline = 5 (2 RootIndex 3 StartRoot 2 EndRoot) Superscript x f (x) = 2.3 (8) Superscript one-half x Baseline = 2.3 (4) Superscript x f (x) = 81 Superscript StartFraction x Over 4 EndFraction Baseline = 3 Superscript x f (x) = three-fourths StartRoot 27 EndRoot ...Find an answer to your question What values of c and d make the equation true? rootindex 3 startroot 162 x superscript c baseline y superscript 5 baseline endro ... When we simplify the cube root of 162, it is 3 as 162 is equal to 3⁴ ... (RootIndex 3 StartRoot x y EndRoot) 16 x Superscript 5 Baseline y cubed (RootIndex 3 StartRoot y EndRoot) ...Which expression is equivalent to RootIndex 4 StartRoot x Superscript 10 Baseline EndRoot? x squared (RootIndex 4 StartRoot x squared EndRoot) x2.2 x cubed (RootIndex 4 StartRoot x EndRoot) x5 star 4.9 /5Learn how to simplify radical expressions by looking for squared values and taking them outside the square root. See the answer, explanation and example for …Expand the following logarithmic expression. log Subscript 5 Baseline (8 StartFraction StartRoot t EndRoot Over v EndFraction) ... squared? 2 log subscript 5 baseline x + log subscript 5 baseline 4 2 log subscript 5 baseline x + log subscript 5 baseline 16 2 log subscript 5 baseline x + 2 log subscript 5 baseline 4 2 log subscript 5 baseline x ...Algebra. Simplify square root of 64x^8. √64x8 64 x 8. Rewrite 64x8 64 x 8 as (8x4)2 ( 8 x 4) 2. √(8x4)2 ( 8 x 4) 2. Pull terms out from under the radical, assuming positive real numbers. 8x4 8 x 4. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step ...Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 StartRoot 5 x Superscript 8 Baseline y squared EndRoot times StartRoot 10 x cubed EndRoot times StartRoot 12 y EndRoot 3 x Superscript 5 Baseline y StartRoot 3 x y EndRoot 10 x Superscript 5 Baseline y StartRoot 6 x y EndRoot 3 x cubed y StartRoot 3 x squared y squared EndRoot ...Let'S multiply and simplify this, so the first thing i would do is come over here and just distribute what was outside the parentheses so to take and distribute to each 1 of these pieces inside. So, let's start with the first piece i will say: 2 times, 3 is 6 and then inside and we'll say 8 times, 10 is 80 and then add the exponents.C. StartFraction 5 Over 25 EndFraction StartRoot StartFraction a Superscript 8 Over a squared EndFraction EndRoot D.StartFraction 6 Over 15 EndFraction a Superscript 4 E. Two-fifths a cubed Which expressions listed on the left are equivalent to StartRoot StartFraction 36 a Superscript 8 Baseline Over 225 a squared EndFraction EndRoot?Work out the perimeter of this semicircle, take pie to be 3.142 radius= 10cm... Answer. Correct answer - Which expression is equivalent to RootIndex 4 StartRoot StartFraction 16 x Superscript 11 Baseline y Superscript 8 Baseline Over 81 x S.08/16/2020. Mathematics; High School; verified. answered • expert verified. ... (RootIndex 3 StartRoot 6 x squared EndRoot) = 4; x (RootIndex 3 StartRoot 6 EndRoot) = x; Solution. Like radicals are radicals that have the same root number and expression under the root. 1) x = No, incorrect;Answer: The Answer Is D. Step-by-step explanation: (RootIndex 8 StartRoot 10 EndRoot Superscript 3 x) It is D because I looked it up each individual answer choice until I got to the same simplified answer as the the question.Assume a greater-than-or-equal-to 0 and b greater-than-or-equal-to 0. 2 a cubed (RootIndex 4 StartRoot 9 b cubed EndRoot) 2 a Superscript 4 Baseline b (RootIndex 4 StartRoot 18 EndRoot) 6 a cubed (RootIndex 4 StartRoot 3 b cubed EndRoot) 12 a Superscript 6 Baseline b (RootIndex 4 StartRoot b EndRoot)5x (8x2 -2x) d. 2x 10x-2x 5. 4x3 4x2 (2^3 32x2 - x3 2x) b. 5 of 6 slide. a. and c. last slide. b. and c. Study with Quizlet and memorize flashcards containing terms like find the simplified product 2x3•18x5, find the simplified product 3 9x4 • 3 3x8, 2 5x3 (-3 10x2 and more.WILL MARK BRAINLIEST Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Superscript 6 Baseline y Superscript 11 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y > 0. answers.
Math. Algebra. Algebra questions and answers. RootIndex 4 StartRoot a Superscript 24 Baseline b Superscript 32 EndRoot4a24b32.. Nail salons in clinton nj
RootIndex 16 StartRoot 4 Superscript 5 Baseline EndRoot StartRoot 2 Superscript 5 EndRoot 2 4. star. 4.7/5. heart. 83. verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, how old is Jennifer ... Simplify the expression below. 12+1 Gunjan, Mala and Amina together can ...Final answer: The cube root of x^{10} when x is -2 simplifies to -8∛(-2), where a = -8 and b = -2.. Explanation: The student has asked to simplify the expression ∛ x^{10} when x is equal to -2. To simplify, we need to break down x^{10} into factors that are suitable for the cube root. Since negative numbers can have real cube roots, we can …Which expression is equivalent to RootIndex 3 StartRoot 256 x Superscript 10 Baseline y Superscript 7 Baseline EndRoot? a.4 x squared y (RootIndex 3 StartRoot x squared y cubed EndRoot) b. 4 x cubed y squared (RootIndex 3 StartRoot 4 x y EndRoot) c. 16 x cubed y squared (RootIndex 3 StartRoot x y EndRoot) d. 16 x Superscript 5 Baseline y cubed ...100 POINTS!!! Which expression is equivalent to RootIndex 4 StartRoot 144 a Superscript 12 Baseline b cubed EndRoot? Assume a greater-than-or-equal-to 0 and b greater-than-or-equal-to 0. 2 a cubed (RootIndex 4 StartRoot 9 b cubed EndRoot) 2 a Superscript 4 Baseline b (RootIndex 4 StartRoot 18 EndRoot) 6 a cubed (RootIndex 4 StartRoot 3 b cubed EndRoot) 12 a Superscript 6 Baseline b (RootIndex ...Dec 7, 2020 · Click here 👆 to get an answer to your question ️ What is the simplified form of StartRoot 64 x Superscript 16 Baseline EndRoot? 8x4 8x8 32x4 32x8 12/16/2019. Mathematics; Middle School ... (RootIndex 3 StartRoot 54 a EndRoot) + 3 (RootIndex 3 StartRoot 2 a b Superscript 6 Baseline EndRoot) A. 6 b squared (RootIndex 3 StartRoot 2 a EndRoot) B. 12 b squared (RootIndex 3 StartRoot 2 a EndRoot C. 6 b squared (RootIndex 6 StartRoot 2 a EndRoot) D. 12 b squared (RootIndex 6 StartRoot 2 a ...To simplify the expression 4r2 + 4r3 + 8r2 + 8r3, combine like terms to get 12r2 + 12r3. ... Simplify: StartRoot 16 r Superscript 6 Baseline EndRoot 4r2 4r3 8r2 8r3 ...Let's see some more problems and our step by step solver will simplify the radical expressions. Please click "Solve Similar" for more examples. Solve similiar problemEnter your own problem. 3. root (3,27x^2y^4) = root (3,3^3x^2y^4) = root (3,3^3z^2y^3y. = root (3,3^3y^3)root (3,x^2y)Which expression is equivalent to RootIndex 4 StartRoot x Superscript 10 Baseline EndRoot? x squared (RootIndex 4 StartRoot x squared EndRoot) x2.2 x cubed (RootIndex 4 StartRoot x EndRoot) x5 star 4.9 /5f left parenthesis x right parenthesisequalsStartFraction e Superscript x Baseline plus 2 e Superscript 5 x Over e Superscript x EndFraction ... Simplify the function using properties of exponents. Given function: \(f(x) = \frac{e^x + 2e^{5x}}{e^x}\) We can use the property of exponents that states \(a^m / a^n = a^{m-n}\) to simplify the ...Step 1. We have "RootIndex 3 StartRoot 16 x Superscript 7 Baseline EndRoot times RootIndex 3 StartRoot 12 x ... View the full answer Answer. Unlock.Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 StartRoot 5 x Superscript 8 Baseline y squared EndRoot times StartRoot 10 x cubed EndRoot times StartRoot 12 y EndRoot 3 x Superscript 5 Baseline y StartRoot 3 x y EndRoot 10 x Superscript 5 Baseline y StartRoot 6 x y EndRoot 3 x cubed y StartRoot 3 x squared y squared EndRoot ...Thanks 16. star. star. star. star. star half outlined. rating answer section. star. star. star. star. star. Answer rating 4.7 ... (RootIndex 12 StartRoot x Superscript 5 EndRoot) D. x6. star. 4.8/5. heart. 91. verified. ... (StartRoot 6 EndRoot minus StartRoot 10 EndRoot) A. 6 StartRoot 2 EndRoot minus 2 StartRoot 30 EndRoot + 6 minus 2 ...May 20, 2020 · Simplify the function f(x) = 7((RootIndex 3 StartRoot 54 EndRoot Superscript x Baseline)). Then answer the questions below. The initial value for the function is . The simplified base for the function is RootIndex 3 StartRoot 2 EndRoot. The domain of the function is . The range of the function is . Move all terms containing x to the left, all other terms to the right. Add '64' to each side of the equation. -64 + 64 + 10000x2 = 0 + 64 Combine like terms: -64 + 64 = 0 0 + 10000x2 = 0 + 64 10000x2 = 0 + 64 Combine like terms: 0 + 64 = 64 10000x2 = 64 Divide each side by '10000'. x2 = 0.0064 Simplifying x2 = 0.0064 Take the square root of ...Precalculus questions and answers. Answer the questions about the following function. f left parenthesis x right parenthesis equals StartFraction x plus 12 Over x minus 8 EndFractionf (x)=x+12 x−8 (a) Is the point left parenthesis 2 comma negative 19 right parenthesis (2,−19) on the graph of f? (b) If x = 3 comma3, what is f (x)?The question asks to simplify the expression StartRoot 144 x Superscript 36 EndRoot. First, we break down the square root of 144, which is 12, as 144 is a perfect square (12 x 12 = 144). Since the exponent of x is even (36), we can take the square root of x³⁶ by halving the exponent, which gives us x¹⁸.To simplify √(128x⁵y⁶ ÷ 2x⁷y⁵), we break down the expression step by step: ... Which expression is equivalent to rootindex 4 startroot startfraction 16 x superscript 11 baseline y superscript 8 baseline over 81 x superscript 7 baseline y superscript 6 baseline endfraction endroot? assume x greater-than 0 and y not-equals 0 ...Free Radicals Calculator - Simplify radical expressions using algebraic rules step-by-stepThe equivalent expression to RootIndex 3 StartRoot StartFraction 75 a Superscript 7 Baseline b Superscript 4 Baseline Over 40 a Superscript 13 Baseline c Superscript 9 Baseline EndFraction EndRoot is StartFraction a cubed b (RootIndex 3 StartRoot 15 b squared EndRoot) Over 2 c cubed EndFraction. To understand why, let's break down the equation..
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